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NEET PHYSICSEasy

The force FF acting on a particle of mass mm is indicated by the force-time graph shown below. The change in momentum of the particle over the time interval from zero to 8 s8 \text{ s} is:

A

24 Ns

B

20 Ns

C

12 Ns

D

6 Ns

Step-by-Step Solution

  1. Concept of Impulse: According to Newton's Second Law of Motion, the rate of change of momentum is equal to the applied force (F=dpdtF = \frac{dp}{dt}). Therefore, the change in momentum (dpdp) is given by FdtF dt.
  2. Graphical Interpretation: The change in momentum (Deltap\\Delta p) over a time interval is the integral of force with respect to time: Δp=Fdt\Delta p = \int F dt. This integral is geometrically equivalent to the area under the Force-time (FtF-t) graph.
  3. Calculation: To determine the change in momentum, one must calculate the area enclosed between the force curve and the time axis from t=0t=0 to t=8 st=8 \text{ s}.
  • Δp=Area under the graph\Delta p = \text{Area under the graph}.
  • (Note: The specific graph image is not included in the input text. However, for the standard NEET 2014 problem associated with this text, the area calculation of the geometric shapes in the graph yields 12 Ns12 \text{ Ns}).
  1. Conclusion: The change in momentum is 12 Ns12 \text{ Ns}.
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