Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A particle (A) is dropped from a height and another particle (B) is thrown in the horizontal direction with a speed of 5 m/sec from the same height. The correct statement is:

Both particles will reach at ground simultaneously

Both particles will reach at ground with same speed

Particle (A) will reach at ground first with respect to particle (B)

Particle (B) will reach at ground first with respect to particle (A)

Step-by-Step Solution

Independence of Motions: The motion of an object can be resolved into independent horizontal ( $x$ ) and vertical ( $y$ ) components. The vertical motion is acted upon by gravity, while the horizontal motion (ignoring air resistance) has zero acceleration .
Vertical Motion Analysis: Both particles start from the same height $h$ . Particle A is dropped, so its initial vertical velocity $u_{yA} = 0$ . Particle B is thrown horizontally, so its initial vertical velocity is also $u_{yB} = 0$ (its initial velocity is entirely horizontal) .
Time of Flight: The time $t$ taken to reach the ground depends only on the vertical parameters: $h = u_y t + \frac{1}{2}gt^2$ . Since $u_y = 0$ for both, $h = \frac{1}{2}gt^2$ implies $t = \sqrt{\frac{2h}{g}}$ .
Conclusion: Since $h$ and $g$ are the same for both particles, the time $t$ is the same. Therefore, they reach the ground simultaneously. (Note: Their final speeds will differ because Particle B has a horizontal velocity component, while Particle A does not).

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