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NEET PHYSICSMedium

Water falls from a height of 60 m60\text{ m} at the rate of 15 kg/s15\text{ kg/s} to operate a turbine. The losses due to frictional force are 10%10\% of the input energy. How much power is generated by the turbine? (g=10 m/s2g = 10\text{ m/s}^2)

A

10.2 kW10.2\text{ kW}

B

8.1 kW8.1\text{ kW}

C

12.3 kW12.3\text{ kW}

D

7.0 kW7.0\text{ kW}

Step-by-Step Solution

Incident power on turbine = d(mgh)dt=ghdmdt=10×60×15=9000 W\frac{d(mgh)}{dt} = gh \frac{dm}{dt} = 10 \times 60 \times 15 = 9000\text{ W}. Now, losses are 10%10\%. Therefore, power generated = (1−10100)×9000=8100 W=8.1 kW\left(1 - \frac{10}{100}\right) \times 9000 = 8100\text{ W} = 8.1\text{ kW}.

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