Back to Directory
NEET PHYSICSEasy

If a soap bubble expands, the pressure inside the bubble:

A

is equal to the atmospheric pressure

B

decreases

C

increases

D

remains the same

Step-by-Step Solution

According to the source material, the pressure inside a spherical soap bubble (PiP_i) is greater than the atmospheric pressure outside (PoP_o) due to surface tension . A soap bubble has two liquid-air interfaces, and the excess pressure is calculated using the formula PiPo=4S/rP_i - P_o = 4S/r, where SS represents the surface tension and rr is the radius of the bubble . From this relation, the total pressure inside is Pi=Po+4S/rP_i = P_o + 4S/r. If the bubble expands, its radius (rr) increases. Since the internal pressure is inversely proportional to the radius, an increase in rr causes the excess pressure term (4S/r4S/r) to become smaller, thus the overall pressure inside the bubble decreases.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: PHYSICS Question for NEET | Sushrut