Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

The position-time (x-t) graph for positive acceleration is:

Option 1

Option 2

Option 3

Option 4

Kinematic Equation: For an object moving with constant acceleration $a$ , the position $x$ at time $t$ is given by the second equation of motion: $x = x_0 + v_0t + \frac{1}{2}at^2$ where $x_0$ is the initial position and $v_0$ is the initial velocity .
Mathematical Analysis: This equation represents a parabola. The nature of the curvature depends on the coefficient of the $t^2$ term, which is $\frac{1}{2}a$ .
Positive Acceleration: If the acceleration $a$ is positive ( $a > 0$ ), the coefficient of $t^2$ is positive. Mathematically, a quadratic function with a positive leading coefficient forms a parabola that opens upwards (concave up). This indicates that the slope of the tangent (velocity) is increasing with time.
Conclusion: The graph for positive acceleration is a curve that bends upwards.

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