Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A missile is fired for a maximum range with an initial velocity of $20 \text{ m/s}$ . If $g=10 \text{ m/s}^2$ , then the range of the missile will be:

50 m

60 m

20 m

40 m

Step-by-Step Solution

Formula for Horizontal Range: The horizontal range $R$ of a projectile projected with initial velocity $v_0$ at an angle $\theta_0$ is given by $R = \frac{v_0^2 \sin 2\theta_0}{g}$ .
Condition for Maximum Range: The range is maximum when $\sin 2\theta_0$ is maximum, i.e., $\sin 2\theta_0 = 1$ , which implies $2\theta_0 = 90^\circ$ or $\theta_0 = 45^\circ$ .
Maximum Range Formula: The maximum horizontal range is $R_{max} = \frac{v_0^2}{g}$ .
Calculation: Given $v_0 = 20 \text{ m/s}$ and $g = 10 \text{ m/s}^2$ . $R_{max} = \frac{(20)^2}{10} = \frac{400}{10} = 40 \text{ m}$

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