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NEET PHYSICSMedium

In an experiment, the percentage of error occurred in the measurement of physical quantities AA, BB, CC and DD are 1%1\%, 2%2\%, 3%3\% and 4%4\% respectively. Then the maximum percentage of X=A2B1/2C1/3D3X = \frac{A^2 B^{1/2}}{C^{1/3} D^3}

error in the measurement XX will be

A

3/13 %

B

16%

C

– 10%

D

10%

Step-by-Step Solution

x=A2B12C13D3x = \frac{A^2 B^{\frac{1}{2}}}{C^{\frac{1}{3}} D^3}

% error, Δxx×100=2ΔAA×100+12ΔBB×100+13ΔCC×100+3ΔDD×100\% \text{ error, } \frac{\Delta x}{x} \times 100 = 2 \frac{\Delta A}{A} \times 100 + \frac{1}{2} \frac{\Delta B}{B} \times 100 + \frac{1}{3} \frac{\Delta C}{C} \times 100 + 3 \frac{\Delta D}{D} \times 100

=2×1%+12×2%+13×3%+3×4%= 2 \times 1\% + \frac{1}{2} \times 2\% + \frac{1}{3} \times 3\% + 3 \times 4\%

=2%+1%+1%+12%= 2\% + 1\% + 1\% + 12\%

=16%= 16\%

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