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NEET PHYSICSEasy

If the cold junction of a thermocouple is kept at 0C0^\circ\text{C} and the hot junction is kept at TCT^\circ\text{C}, then the relation between neutral temperature (TnT_n) and temperature of inversion (TiT_i) is:

A

Tn=Ti2T_n = \frac{T_i}{2}

B

Tn=2TiT_n = 2T_i

C

Tn=TiTT_n = T_i - T

D

Tn=Ti+TT_n = T_i + T

Step-by-Step Solution

For a given thermocouple, the temperature difference between the neutral temperature (TnT_n) and the cold junction temperature (TcT_c) is equal to the temperature difference between the inversion temperature (TiT_i) and the neutral temperature (TnT_n). This can be mathematically expressed as: TnTc=TiTnT_n - T_c = T_i - T_n     2Tn=Ti+Tc\implies 2T_n = T_i + T_c Given that the cold junction is kept at 0C0^\circ\text{C} (Tc=0CT_c = 0^\circ\text{C}), 2Tn=Ti+02T_n = T_i + 0     Tn=Ti2\implies T_n = \frac{T_i}{2}

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