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NEET PHYSICSEasy

The distance covered by a body of mass 5 g5 \text{ g} having linear momentum 0.3 kg m/s0.3 \text{ kg m/s} in 5 s5 \text{ s} is:

A

300 m

B

30 m

C

3 m

D

0.3 m

Step-by-Step Solution

  1. Identify Given Data:
  • Mass (mm) = 5 g=5×10−3 kg5 \text{ g} = 5 \times 10^{-3} \text{ kg}.
  • Linear Momentum (pp) = 0.3 kg m/s0.3 \text{ kg m/s}.
  • Time (tt) = 5 s5 \text{ s}.
  1. Identify Relationships:
  • Momentum is the product of mass and velocity: p=mvp = mv [Source 121].
  • For a body moving with constant momentum (and thus constant velocity), distance is given by d=v×td = v \times t [Source 41].
  1. Calculate Velocity (vv): v=pm=0.35×10−3=0.30.005=3005=60 m/sv = \frac{p}{m} = \frac{0.3}{5 \times 10^{-3}} = \frac{0.3}{0.005} = \frac{300}{5} = 60 \text{ m/s}
  2. Calculate Distance (dd): d=v×t=60 m/s×5 s=300 md = v \times t = 60 \text{ m/s} \times 5 \text{ s} = 300 \text{ m}
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