Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

In the given figure, a diode D is connected to an external resistance $R = 100 \, \Omega$ and an e.m.f of $3.5\text{ V}$ . If the barrier potential developed across the diode is $0.5\text{ V}$ , the current in the circuit will be:

30 mA

40 mA

20 mA

35 mA

Step-by-Step Solution

Identify the Given Data: E.m.f of the battery, $V = 3.5\text{ V}$ ; Barrier potential of the diode, $V_d = 0.5\text{ V}$ ; External resistance, $R = 100 \, \Omega$ .
Calculate Net Voltage: Assuming the diode is forward-biased (which allows current to flow), it drops a voltage equal to its barrier potential. The net effective voltage driving the current through the external resistor is $V_{net} = V - V_d = 3.5\text{ V} - 0.5\text{ V} = 3.0\text{ V}$ .
Calculate Current: Using Ohm's law, the current in the circuit is $I = \frac{V_{net}}{R} = \frac{3.0\text{ V}}{100 \, \Omega} = 0.03\text{ A} = 30\text{ mA}$ .

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