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NEET PHYSICSEasy

A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux for the surface of the cylinder is given by

A

2\pi R²E

B

\pi R²/E

C

(\pi R² - \pi R)/E

D

Zero

Step-by-Step Solution

The cylinder consists of three surfaces: two flat circular faces (caps) and one curved surface.

  1. Curved Surface: The area vector is perpendicular to the surface (radially outward), while the electric field is parallel to the axis. The angle between them is 9090^\circ. Flux Φcurved=EdAcos90=0\Phi_{curved} = \int E dA \cos 90^\circ = 0.
  2. Circular Faces: The area vectors for the two faces point outward in opposite directions (parallel and anti-parallel to the field).
  • For the face where the field enters, θ=180\theta = 180^\circ, so Φin=E(πR2)cos180=πR2E\Phi_{in} = E(\pi R^2) \cos 180^\circ = -\pi R^2 E.
  • For the face where the field leaves, θ=0\theta = 0^\circ, so Φout=E(πR2)cos0=+πR2E\Phi_{out} = E(\pi R^2) \cos 0^\circ = +\pi R^2 E.
  1. Total Flux: The net flux is the sum of fluxes through all surfaces: Φtotal=πR2E+πR2E+0=0\Phi_{total} = -\pi R^2 E + \pi R^2 E + 0 = 0.

Alternatively, according to Gauss's Law, the net flux through a closed surface is zero if there is no charge enclosed within it (qenclosed=0q_{enclosed} = 0). Since the cylinder is merely placed in an external field and encloses no charge, the total flux is zero .

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