Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

Two resistors of resistance, $100\text{ }\Omega$ and $200\text{ }\Omega$ are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in $100\text{ }\Omega$ to that in $200\text{ }\Omega$ in a given time is

$1:2$

$2:1$

$1:4$

$4:1$

Step-by-Step Solution

For parallel combination, power $P = \frac{V^2}{R}$ . Therefore, $\frac{P_1}{P_2} = \frac{R_2}{R_1} = \frac{200}{100} = \frac{2}{1}$ .

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