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NEET PHYSICSEasy

Whose dimensions are ML2T−1ML^2T^{-1}?

A

Torque

B

Angular momentum

C

Power

D

Work

Step-by-Step Solution

  1. Analyze the given dimension: The dimensional formula is [ML2T−1][ML^2T^{-1}].
  2. Check Option B (Angular momentum): Angular momentum (LL) is defined as the cross product of position vector and linear momentum (L=r×p=mvrL = r \times p = mvr).
  • Mass (mm): [M][M]
  • Velocity (vv): [LT−1][LT^{-1}]
  • Distance (rr): [L][L]
  • Dimensions of LL: [M]×[LT−1]×[L]=[ML2T−1][M] \times [LT^{-1}] \times [L] = [ML^2T^{-1}].
  1. Check other options for verification:
  • Torque (ττ): Defined as force ×\times perpendicular distance. Dimensions: [MLT−2]×[L]=[ML2T−2][MLT^{-2}] \times [L] = [ML^2T^{-2}].
  • Work (WW): Defined as force ×\times displacement. Dimensions: [MLT−2]×[L]=[ML2T−2][MLT^{-2}] \times [L] = [ML^2T^{-2}].
  • Power (PP): Defined as work done per unit time. Dimensions: [ML2T−2]/[T]=[ML2T−3][ML^2T^{-2}] / [T] = [ML^2T^{-3}].
  1. Conclusion: The dimensions [ML2T−1][ML^2T^{-1}] belong to Angular momentum.
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