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NEET PHYSICSMedium

The magnitude and direction of the current in the following circuit is

A

0.2 A from B to A through E

B

0.5 A from A to B through E

C

5/9 A from A to B through E

D

1.5 A from B to A through E

Step-by-Step Solution

Using Kirchhoff's loop rule for the circuit: The total EMF in the loop is 10−5=510 - 5 = 5 V. The total resistance is 2+1+7=10Ω2 + 1 + 7 = 10 \Omega. Current I=V/R=5/10=0.5I = V/R = 5 / 10 = 0.5 A. Since the 10V battery is stronger, the current flows from A to B through the branch containing the 5V battery.

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