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The potential differences across the resistance, capacitance and inductance are 80 V, 40 V and 100 V respectively in an LCR circuit. What is the power factor of this circuit?

A

0.4

B

0.5

C

0.8

D

1

Step-by-Step Solution

In a series LCR circuit, the total voltage (V) is the phasor sum of the voltages across the components. Since the voltage across the inductor (VLV_L) and the capacitor (VCV_C) are 180180^\circ out of phase, the net reactive voltage is VLVCV_L - V_C (or VCVLV_C - V_L). The voltage across the resistor (VRV_R) is 9090^\circ out of phase with the net reactive voltage. Using the values given: VR=80V_R = 80 V, VC=40V_C = 40 V, VL=100V_L = 100 V. The net supply voltage VV is given by V=VR2+(VLVC)2=802+(10040)2=802+602=6400+3600=10000=100V = \sqrt{V_R^2 + (V_L - V_C)^2} = \sqrt{80^2 + (100 - 40)^2} = \sqrt{80^2 + 60^2} = \sqrt{6400 + 3600} = \sqrt{10000} = 100 V. The power factor (cosϕ\cos \phi) is defined as the ratio of resistance to impedance (R/ZR/Z) or equivalently the ratio of the potential difference across the resistor to the total potential difference (VR/VV_R/V) . Power Factor = VR/V=80/100=0.8V_R / V = 80 / 100 = 0.8.

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