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NEET PHYSICSMedium

If E and G respectively denote energy and gravitational constant, then EG\frac{E}{G} has the dimensions of

A

[M^2] [L^{-1}] [T^0]

B

[M] [L^{-1}] [T^{-1}]

C

[M] [L^0] [T^0]

D

[M^2] [L^{-2}] [T^{-1}]

Step-by-Step Solution

Energy E=[ML2T−2]E = [ML^2T^{-2}]. Gravitational constant G=[M−1L3T−2]G = [M^{-1}L^3T^{-2}]. Therefore, EG=[ML2T−2][M−1L3T−2]=[M2L−1T0]\frac{E}{G} = \frac{[ML^2T^{-2}]}{[M^{-1}L^3T^{-2}]} = [M^2L^{-1}T^0].

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