Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

After passing through a polarizer, a linearly polarized light of intensity $I$ is incident on an analyser making an angle of $30^{\circ}$ with the axes of the polariser. The intensity of light emitted from the analyser will be:

I/2

I/3

3I/4

2I/3

Step-by-Step Solution

Concept (Malus' Law): When a beam of completely plane-polarized light is incident on an analyser, the resultant intensity $I'$ transmitted from the analyser is given by the relation $I' = I \cos^2 \theta$ , where $I$ is the intensity of incident polarized light and $\theta$ is the angle between the transmission axes of the polarizer and the analyser.
Given Values:

Incident Intensity = $I$
Angle $\theta = 30^{\circ}$

Calculation: $I' = I \cos^2(30^{\circ})$ $I' = I \left( \frac{\sqrt{3}}{2} \right)^2$ $I' = I \left( \frac{3}{4} \right) = \frac{3I}{4}$
Conclusion: The intensity of the light emitted is $3I/4$ .

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