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NEET PhysicsMedium

A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to L1L_1 when mass M is suspended from its free end. The expression for Young's modulus is :

1

MgL1AL\frac{MgL_1}{AL}

2

Mg(L1−L)AL\frac{Mg(L_1-L)}{AL}

3

MgLAL1\frac{MgL}{AL_1}

4

MgLA(L1−L)\frac{MgL}{A(L_1-L)}

Step-by-Step Solution

Stress = MgA\frac{Mg}{A}. Strain = ΔLL=L1−LL\frac{\Delta L}{L} = \frac{L_1-L}{L}. Young's modulus = StressStrain=MgLA(L1−L)\frac{\text{Stress}}{\text{Strain}} = \frac{MgL}{A(L_1-L)}.

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