Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

Two conducting circular loops of radii $R_1$ and $R_2$ are placed in the same plane with their centres coinciding. If $R_1 >> R_2$ , the mutual inductance $M$ between them will be directly proportional to

\frac{R_1}{R_2}

\frac{R_2}{R_1}

\frac{R_1^2}{R_2}

\frac{R_2^2}{R_1}

Step-by-Step Solution

Magnetic field at centre $B = \frac{\mu_0 i}{2R_1}$ . Magnetic flux through inner coil $\phi = B \times \pi R_2^2 = \frac{\mu_0 i}{2R_1} \times \pi R_2^2$ . As per definition, $\phi = Mi$ , so $M = \frac{\mu_0 \pi R_2^2}{2 R_1}$ . Therefore, $M \propto \frac{R_2^2}{R_1}$ .

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started