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NEET PHYSICSEasy

A parallel plate condenser has a uniform electric field E (V/m) in the space between the plates. If the distance between the plates is d (m) and area of each plate is A (m²), the energy (joule) stored in the condenser is:

A

1/2 ε₀E²

B

ε₀EAd

C

1/2 ε₀E²Ad

D

E²Ad/ε₀

Step-by-Step Solution

The energy stored (UU) in a capacitor is given by the formula U=12CV2U = \frac{1}{2}CV^2. For a parallel plate capacitor, the capacitance is C=ε0AdC = \frac{\varepsilon_0 A}{d} and the potential difference is related to the electric field by V=EdV = Ed.

Substituting these values into the energy equation: U=12(ε0Ad)(Ed)2U = \frac{1}{2} \left( \frac{\varepsilon_0 A}{d} \right) (Ed)^2 U=12(ε0Ad)(E2d2)U = \frac{1}{2} \left( \frac{\varepsilon_0 A}{d} \right) (E^2 d^2) U=12ε0E2(Ad)U = \frac{1}{2} \varepsilon_0 E^2 (Ad)

Alternatively, the energy density (energy per unit volume) is u=12ε0E2u = \frac{1}{2}\varepsilon_0 E^2. The total energy is the product of energy density and the volume of the space between the plates (Volume=A×dVolume = A \times d). Thus, U=u×Volume=12ε0E2AdU = u \times Volume = \frac{1}{2}\varepsilon_0 E^2 Ad.

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