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NEET PHYSICSMedium

An n-p-n transistor is connected in the common base configuration in a given amplifier. A load resistance of $800\, \Omega$ is connected in the collector circuit and the voltage drop across it is $0.8\text{ V}$ . If the current amplification factor is $0.96$ and the input resistance of the circuit is $192\, \Omega$ , the voltage gain and the power gain of the amplifier will respectively be:

A

3.69, 3.84

B

4, 4

C

4, 3.69

D

4, 3.84

Step-by-Step Solution

Identify the Given Data: Output/Load resistance, $R_{out} = 800\, \Omega$ Input resistance, $R_{in} = 192\, \Omega$

Current amplification factor (common base), $\alpha = 0.96$

Calculate Voltage Gain ( $A_v$ ): The voltage gain is the product of the current gain and the resistance gain ( $R_{out}/R_{in}$ ).

$A_v = \alpha \times \frac{R_{out}}{R_{in}} = 0.96 \times \frac{800}{192} = 0.96 \times \frac{25}{6} = 4$

Calculate Power Gain ( $A_p$ ): The power gain is the product of voltage gain and current gain.

$A_p = A_v \times \alpha = 4 \times 0.96 = 3.84$

Conclusion: The voltage gain is $4$ and the power gain is $3.84$ . (Note: The $0.8\text{ V}$ drop across the load is extraneous information not required to find the gains).

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