According to Wien's displacement law, $\lambda_m T = b$, where $\lambda_m$ is the wavelength corresponding to maximum spectral emissive power, $T$ is the absolute temperature, and $b$ is Wien's constant. Given: $T = 5760 \text{ K}$ and $b = 2.88 \times 10^6 \text{ nm K}$. $\lambda_m = \frac{b}{T} = \frac{2.88 \times 10^6}{5760} = 500 \text{ nm}$. Therefore, the maximum energy is radiated at a wavelength of $500 \text{ nm}$. Since $U_2$ corresponds to the energy radiated at $500 \text{ nm}$, it is the maximum among the given energies. Thus, $U_2 > U_1$ and $U_2 > U_3$. Also, a black body emits continuous radiation over all wavelengths, so $U_1 \neq 0$ and $U_3 \neq 0$. The only correct statement among the options is $U_2 > U_1$.