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NEET PHYSICSEasy

A body of mass 60 g60 \text{ g} experiences a gravitational force of 3.0 N3.0 \text{ N} when placed at a particular point. The magnitude of the gravitational field intensity at that point is:

A

180 N/kg180 \text{ N/kg}

B

0.05 N/kg0.05 \text{ N/kg}

C

50 N/kg50 \text{ N/kg}

D

20 N/kg20 \text{ N/kg}

Step-by-Step Solution

  1. Definition: Gravitational field intensity (EE or gg) at a point is defined as the gravitational force experienced by a unit mass placed at that point. The formula is given by E=FmE = \frac{F}{m}.
  2. Given Data:
  • Gravitational Force, F=3.0 NF = 3.0 \text{ N}.
  • Mass of the body, m=60 gm = 60 \text{ g}.
  1. Unit Conversion: Convert mass into SI units (kg). m=60×10−3 kg=0.06 kgm = 60 \times 10^{-3} \text{ kg} = 0.06 \text{ kg}
  2. Calculation: Substitute the values into the formula: E=3.0 N0.06 kg=3006 N/kg=50 N/kgE = \frac{3.0 \text{ N}}{0.06 \text{ kg}} = \frac{300}{6} \text{ N/kg} = 50 \text{ N/kg}
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