Back to Directory
NEET PHYSICSEasy

The mass of a lift is 2000 kg2000 \text{ kg}. When the tension in the supporting cable is 28000 N28000 \text{ N}, then its acceleration is: (Take g=10 m/s2g=10 \text{ m/s}^2)

A

30 m/s230 \text{ m/s}^2 downwards

B

4 m/s24 \text{ m/s}^2 upwards

C

4 m/s24 \text{ m/s}^2 downwards

D

14 m/s214 \text{ m/s}^2 upwards

Step-by-Step Solution

  1. Identify Forces: The forces acting on the lift are the tension TT (acting upwards) and the weight mgmg (acting downwards).
  2. Compare Forces:
  • Upward force T=28000 NT = 28000 \text{ N}.
  • Downward force W=mg=2000×10=20000 NW = mg = 2000 \times 10 = 20000 \text{ N}.
  • Since T>mgT > mg, the net force is directed upwards, meaning the lift accelerates upwards.
  1. Apply Newton's Second Law: The net force FnetF_{net} equals mass times acceleration (mama). Fnet=T−mg=maF_{net} = T - mg = ma
  2. Calculation: 28000−20000=2000×a28000 - 20000 = 2000 \times a 8000=2000×a8000 = 2000 \times a a=80002000=4 m/s2a = \frac{8000}{2000} = 4 \text{ m/s}^2 (Reference: NCERT Class 11, Physics Part I, Chapter 5: Laws of Motion, Section 5.5).
Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started