Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

The radius of circle, the period of revolution, initial position and sense of revolution are indicated in the fig. y - projection of the radius vector of rotating particle P is :

$y(t) = -3 \cos 2\pi t$ , where y in m

$y(t) = 4 \sin \left( \frac{\pi t}{2} \right)$ , where y in m

$y(t) = 3 \cos \left( \frac{3\pi t}{2} \right)$ , where y in m

$y(t) = 3 \cos \left( \frac{\pi t}{2} \right)$ , where y in m

Step-by-Step Solution

At $t = 0$ , y displacement is maximum, so equation will be cosine function. $T = 4 \text{ s}$ . $\omega = \frac{2\pi}{T} = \frac{2\pi}{4} = \frac{\pi}{2} \text{ rad/s}$ . $y = a \cos \omega t = 3 \cos \frac{\pi}{2} t$ .

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