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NEET PHYSICSMedium

A screw gauge gives the following readings when used to measure the diameter of a wire. Main scale reading : 0 mm. Circular scale reading : 52 divisions. Given that 1 mm on main scale corresponds to 100 divisions on the circular scale. The diameter of the wire from the above data is

1

0.52 cm

2

0.026 cm

3

0.26 cm

4

0.052 cm

Step-by-Step Solution

Here, pitch of the screw gauge, P=1P = 1 mm. Number of circular division, n=100n = 100. Thus least count LC=Pn=1100=0.01LC = \frac{P}{n} = \frac{1}{100} = 0.01 mm = 0.0010.001 cm. So, diameter of the wire = MSR+(CSR×LC)=0+(52×0.001MSR + (CSR \times LC) = 0 + (52 \times 0.001 cm) = 0.0520.052 cm.

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