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NEET PHYSICSEasy

For a smoothly running analog clock, the ratio of the number of rotations made in a day by the hour hand to the second hand, respectively, is:

A

24 : 1

B

1 : 720

C

1 : 60

D

2 : 5

Step-by-Step Solution

  1. Analyze the Motion of the Hour Hand: The hour hand completes one full rotation in 12 hours. In one day (24 hours), the number of rotations made by the hour hand is: Nhour=24 hours12 hours/rotation=2 rotationsN_{hour} = \frac{24 \text{ hours}}{12 \text{ hours/rotation}} = 2 \text{ rotations}

  2. Analyze the Motion of the Second Hand: The second hand completes one full rotation in 1 minute. There are 24×60=144024 \times 60 = 1440 minutes in a day.

  • Therefore, in one day, the number of rotations made by the second hand is: Nsecond=1440 rotationsN_{second} = 1440 \text{ rotations}
  1. Calculate the Ratio: The ratio of the number of rotations of the hour hand to the second hand is: Ratio=NhourNsecond=21440\text{Ratio} = \frac{N_{hour}}{N_{second}} = \frac{2}{1440} Simplifying the fraction: Ratio=1720\text{Ratio} = \frac{1}{720}
  • Thus, the ratio is 1:7201:720.
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