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NEET PHYSICSMedium

In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1 m away, was found to be 0.2°. What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? (μwater=4/3\mu_{water} = 4/3)

A

0.266°

B

0.15°

C

0.05°

D

0.1°

Step-by-Step Solution

In air, θ0=βD\theta_0 = \frac{\beta}{D}. In water, the angular width becomes θw=θ0μ=0.2°4/3=0.15°\theta_w = \frac{\theta_0}{\mu} = \frac{0.2°}{4/3} = 0.15°.

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