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NEET PHYSICSEasy

It is easier to draw up a wooden block along a smooth inclined plane than to haul it vertically, principally because:

A

The friction is reduced

B

The mass becomes smaller

C

Only a part of the weight has to be overcome

D

‘g’ becomes smaller

Step-by-Step Solution

  1. Vertical Lifting: To lift a block of mass mm vertically upwards, the applied force FverticalF_{vertical} must oppose the full force of gravity (weight). Thus, Fvertical=mgF_{vertical} = mg.
  2. Inclined Plane: On a smooth inclined plane making an angle θ\theta with the horizontal, the weight mgmg is resolved into two components:
  • Perpendicular to the plane: mgcosθmg \cos \theta (balanced by normal reaction).
  • Parallel to the plane: mgsinθmg \sin \theta (opposing upward motion).
  1. Comparison: The force required to pull the block up the smooth incline is Fincline=mgsinθF_{incline} = mg \sin \theta [Source 72].
  2. Conclusion: Since sinθ<1\sin \theta < 1 for any acute angle, Fincline<FverticalF_{incline} < F_{vertical}. The effort is reduced because only the component (part) of the weight (mgsinθmg \sin \theta) needs to be overcome, not the entire weight (mgmg). Mass and gg remain constant.
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