Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

The output ( $X$ ) of the logic circuit shown in the figure will be:

$X = \overline{A} \cdot \overline{B}$

$X = \overline{A \cdot B}$

$X = A \cdot B$

$X = \overline{A + B}$

Analyze the Circuit: To determine the output $X$ of a logic circuit, we must write down the Boolean expression for each logic gate step-by-step from the inputs to the output.
Identify the Gates: Although the specific circuit diagram is missing from the prompt, questions of this type typically involve combinations of basic or universal gates. A common configuration from NEET 2013 involves inputs $A$ and $B$ fed into a NAND gate, producing $\overline{A \cdot B}$ , which is then passed through a NOT gate (or another NAND with tied inputs).
Evaluate Expression: Passing $\overline{A \cdot B}$ through a NOT gate complements it again, yielding $X = \overline{\overline{A \cdot B}} = A \cdot B$ .
Alternative Configuration: If inputs are passed through NOT gates first (yielding $\overline{A}$ and $\overline{B}$ ) and then into a NOR gate, De Morgan's Law gives $X = \overline{\overline{A} + \overline{B}} = A \cdot B$ .
Conclusion: Based on the probable answer, the circuit acts as an AND gate, giving the output $X = A \cdot B$ .

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