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NEET PhysicsEasy

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is :

1

0.01 mm

2

0.25 mm

3

0.5 mm

4

1.0 mm

Step-by-Step Solution

Least count = PitchNumber of divisions on circular scale\frac{\text{Pitch}}{\text{Number of divisions on circular scale}}. Therefore, 0.01 mm=Pitch500.01 \text{ mm} = \frac{\text{Pitch}}{50}, which gives Pitch=0.5 mm\text{Pitch} = 0.5 \text{ mm}.

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