Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

In a potentiometer circuit a cell of EMF $1.5 \V$ gives balance point at $36 \cm$ length of wire. If another cell of EMF $2.5 \V$ replaces the first cell, then at what length of the wire, the balance point occurs?

$60 \cm$

$21.6 \cm$

$64 \cm$

$62 \cm$

Step-by-Step Solution

From the application of potentiometer to compare two cells of emfs $E_1$ and $E_2$ by balancing lengths $\ell_1$ and $\ell_2$ , we have $E_1/E_2 = \ell_1/\ell_2$ . Thus, $\ell_2 = \ell_1(E_2/E_1) = (36 \cm)(2.5 \V / 1.5 \V) = 60 \cm$ .

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