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NEET PHYSICSEasy

Four point charges qA=2μCq_A = 2 \mu\text{C}, qB=5μCq_B = -5 \mu\text{C}, qC=2μCq_C = 2 \mu\text{C}, and qD=5μCq_D = -5 \mu\text{C} are located at the corners of a square ABCD of side 10 cm. The force on a charge of 1μC1 \mu\text{C} placed at the centre of the square is:

A

22 N

B

11 N

C

55 N

D

0 N

Step-by-Step Solution

The centre of the square is equidistant from all four corners. The charges at opposite corners A and C are equal (qA=qC=2μCq_A = q_C = 2 \mu\text{C}) and positive; therefore, the repulsive forces they exert on the central 1μC1 \mu\text{C} charge are equal in magnitude and opposite in direction, cancelling each other out. Similarly, the charges at opposite corners B and D are equal (qB=qD=5μCq_B = q_D = -5 \mu\text{C}) and negative; the attractive forces they exert on the central charge are also equal and opposite, cancelling each other out. Consequently, the net electrostatic force on the charge at the centre is zero. (See NCERT Physics Class 12, Exercise 1.6).

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