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NEET PHYSICSMedium

A vehicle travels half the distance with speed vv and the remaining distance with speed 2v2v. Its average speed is

1

v3\frac{v}{3}

2

2v3\frac{2v}{3}

3

4v3\frac{4v}{3}

4

3v4\frac{3v}{4}

Step-by-Step Solution

Average speed vavg=Total DistanceTotal Timev_{avg} = \frac{\text{Total Distance}}{\text{Total Time}}. Let total distance be 2d2d. Time t1=d/vt_1 = d/v, t2=d/2vt_2 = d/2v. vavg=2dd/v+d/2v=2d2d+d2v=2d3d2v=4v3v_{avg} = \frac{2d}{d/v + d/2v} = \frac{2d}{\frac{2d+d}{2v}} = \frac{2d}{\frac{3d}{2v}} = \frac{4v}{3}.

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