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NEET PHYSICSMedium

In a vernier callipers, (N+1)(N+1) divisions of the vernier scale coincide with NN divisions of the main scale. If 1 MSD1 \text{ MSD} represents 0.1 mm0.1 \text{ mm}, the vernier constant (in cm) is:

A

1 / [100(N+1)]

B

100N

C

10(N+1)

D

1 / (10N)

Step-by-Step Solution

The Vernier constant (VC), or least count, is defined as the difference between the value of one main scale division (MSD) and one vernier scale division (VSD) .

  1. Establish the relationship between VSD and MSD: The problem states that (N+1)(N+1) VSDs coincide with NN MSDs. Therefore, 1 VSD=NN+1 MSD1 \text{ VSD} = \frac{N}{N+1} \text{ MSD}.

  2. Apply the Vernier Constant formula: VC=1 MSD1 VSDVC = 1 \text{ MSD} - 1 \text{ VSD} VC=1 MSD(NN+1) MSDVC = 1 \text{ MSD} - \left(\frac{N}{N+1}\right) \text{ MSD} VC=MSD(1NN+1)=MSDN+1VC = \text{MSD} \left(1 - \frac{N}{N+1}\right) = \frac{\text{MSD}}{N+1}.

  3. Substitute given values and convert units: We are given 1 MSD=0.1 mm1 \text{ MSD} = 0.1 \text{ mm}. To find the constant in cm, we use the conversion 1 mm=0.1 cm1 \text{ mm} = 0.1 \text{ cm}, thus 0.1 mm=0.01 cm0.1 \text{ mm} = 0.01 \text{ cm} . VC=0.01N+1 cm=1100(N+1) cmVC = \frac{0.01}{N+1} \text{ cm} = \frac{1}{100(N+1)} \text{ cm}.

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