The maximum electromotive force ($\varepsilon_{max}$) generated in an AC generator is given by the formula: $\varepsilon_{max} = NBA\omega$

1. Identify Given Values: Number of turns ($N$) = 100 Area of the coil ($A$) = $1 \text{ m}^2$ Magnetic Field Strength ($B$) = $0.05 \text{ T}$ Frequency of rotation ($\nu$) = $1 \text{ revolution per second} = 1 \text{ Hz}$

2. Calculate Angular Velocity ($\omega$): $\omega = 2\pi\nu = 2\pi(1) = 2\pi \text{ rad/s}$

3. Calculate Maximum EMF: Substituting the values into the formula: $\varepsilon_{max} = 100 \times 0.05 \times 1 \times 2\pi$ $\varepsilon_{max} = 5 \times 2\pi$ $\varepsilon_{max} = 10\pi$

Using the approximation $\pi \approx 3.14$: $\varepsilon_{max} = 10 \times 3.14 = 31.4 \text{ V}$