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NEET PHYSICSMedium

Dependence of intensity of gravitational field (E) of earth with distance (r) from centre of earth is correctly represented by:

A

Graph showing linear increase (E \propto r) for r < R and decrease (E \propto 1/r²) for r > R

B

Graph showing constant E

C

Graph showing exponential increase

D

Graph showing linear decrease

Step-by-Step Solution

The intensity of the gravitational field (EE) or acceleration due to gravity (gg) varies with distance rr from the centre of the Earth:

  1. Inside the Earth (r<Rr < R): Assuming uniform density, the field is directly proportional to the distance from the centre. E=GMR3rE = \frac{GM}{R^3}r, so ErE \propto r. This is represented by a straight line passing through the origin.
  2. At the surface (r=Rr = R): The field reaches its maximum value, E=GMR2E = \frac{GM}{R^2}.
  3. Outside the Earth (r>Rr > R): The field behaves as if the entire mass is concentrated at the centre and follows the inverse square law. E=GMr2E = \frac{GM}{r^2}, so E1r2E \propto \frac{1}{r^2}. This is represented by a rectangular hyperbola decreasing as rr increases. Therefore, the correct graph shows a linear increase up to r=Rr=R followed by a curvilinear decrease.
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