The displacement current ($I_d$) in the capacitor is equal to the conduction current ($I_c$) flowing in the series circuit. In an AC circuit, the peak displacement current corresponds to the peak conduction current ($I_0$). Given: Resistance $R = 100 \, \Omega$, Capacitive Reactance $X_C = 100 \, \Omega$, Source Voltage $V_{rms} = 220$ V. The impedance of the series RC circuit is $Z = \sqrt{R^2 + X_C^2} = \sqrt{100^2 + 100^2} = 100\sqrt{2} \, \Omega$ . The peak voltage of the source is $V_0 = \sqrt{2} V_{rms} = 220\sqrt{2}$ V. The peak current is $I_0 = \frac{V_0}{Z} = \frac{220\sqrt{2}}{100\sqrt{2}} = 2.2$ A . The condition '50% charged' refers to the instantaneous state, but the peak value of the current is a constant property of the steady-state AC circuit.