The angle of 1′1'1′ (minute of an arc) in radian is nearly equal to:
2.91×10−4 rad2.91 \times 10^{-4} \text{ rad}2.91×10−4 rad
4.85×10−4 rad4.85 \times 10^{-4} \text{ rad}4.85×10−4 rad
4.80×10−6 rad4.80 \times 10^{-6} \text{ rad}4.80×10−6 rad
1.75×10−2 rad1.75 \times 10^{-2} \text{ rad}1.75×10−2 rad
We know that 360∘=2π rad360^{\circ} = 2\pi \text{ rad}360∘=2π rad, so 1∘=π180 rad≈1.745×10−2 rad1^{\circ} = \frac{\pi}{180} \text{ rad} \approx 1.745 \times 10^{-2} \text{ rad}1∘=180π rad≈1.745×10−2 rad. Since 111 minute of an arc (1′1'1′) is 160\frac{1}{60}601 of a degree: 1′=1∘60=1.745×10−260 rad≈2.908×10−4 rad1' = \frac{1^{\circ}}{60} = \frac{1.745 \times 10^{-2}}{60} \text{ rad} \approx 2.908 \times 10^{-4} \text{ rad}1′=601∘=601.745×10−2 rad≈2.908×10−4 rad. Rounding off to three significant figures, we get 1′≈2.91×10−4 rad1' \approx 2.91 \times 10^{-4} \text{ rad}1′≈2.91×10−4 rad.
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