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NEET PHYSICSMedium

Two particles A and B move with constant velocities v1\mathbf{v}_1 and v2\mathbf{v}_2. At the initial moment, their position vectors are r1\mathbf{r}_1 and r2\mathbf{r}_2 respectively. The condition for particles A and B for their collision is:

A

r1r2r1r2=v2v1v2v1\frac{\mathbf{r}_1 - \mathbf{r}_2}{|\mathbf{r}_1 - \mathbf{r}_2|} = \frac{\mathbf{v}_2 - \mathbf{v}_1}{|\mathbf{v}_2 - \mathbf{v}_1|}

B

r1v1=r2v2\mathbf{r}_1 \cdot \mathbf{v}_1 = \mathbf{r}_2 \cdot \mathbf{v}_2

C

r1×v1=r2×v2\mathbf{r}_1 \times \mathbf{v}_1 = \mathbf{r}_2 \times \mathbf{v}_2

D

r1r2=v1v2\mathbf{r}_1 - \mathbf{r}_2 = \mathbf{v}_1 - \mathbf{v}_2

Step-by-Step Solution

For two particles to collide, they must be at the same position at the same time tt (t>0t > 0). Let the collision occur at time tt. Position of particle A at time tt: rA=r1+v1t\mathbf{r}_A = \mathbf{r}_1 + \mathbf{v}_1 t Position of particle B at time tt: rB=r2+v2t\mathbf{r}_B = \mathbf{r}_2 + \mathbf{v}_2 t For collision, rA=rB\mathbf{r}_A = \mathbf{r}_B: r1+v1t=r2+v2t\mathbf{r}_1 + \mathbf{v}_1 t = \mathbf{r}_2 + \mathbf{v}_2 t r1r2=(v2v1)t\mathbf{r}_1 - \mathbf{r}_2 = (\mathbf{v}_2 - \mathbf{v}_1) t Since time tt is a positive scalar, the vector representing relative initial displacement (r1r2)(\mathbf{r}_1 - \mathbf{r}_2) must be in the same direction as the relative velocity vector (v2v1)(\mathbf{v}_2 - \mathbf{v}_1). This implies that their unit vectors must be equal: r1r2r1r2=v2v1v2v1\frac{\mathbf{r}_1 - \mathbf{r}_2}{|\mathbf{r}_1 - \mathbf{r}_2|} = \frac{\mathbf{v}_2 - \mathbf{v}_1}{|\mathbf{v}_2 - \mathbf{v}_1|},

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