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NEET PHYSICSMedium

A stone falls freely under gravity. It covers distances h₁, h₂ and h₃ in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h₁, h₂ and h₃ is:

A

h₁ = h₂/3 = h₃/5

B

h₂ = 3h₁ and h₃ = 3h₂

C

h₁ = h₂ = h₃

D

h₁ = 2h₂ = 3h₃

Step-by-Step Solution

This problem illustrates Galileo's law of odd numbers. For a body falling freely from rest, the distances traversed during equal intervals of time stand to one another in the same ratio as the odd numbers beginning with unity (1: 3: 5: 7...).

  1. Identify Conditions: The stone falls under gravity (uniform acceleration, a=ga=g) starting from rest (u=0u=0). The time intervals are equal (t=5t = 5 s).
  2. Apply Galileo's Law: Distance covered in the 1st interval (h1h_1) is proportional to 1. Distance covered in the 2nd interval (h2h_2) is proportional to 3. Distance covered in the 3rd interval (h3h_3) is proportional to 5. Therefore, the ratio is h1:h2:h3=1:3:5h_1 : h_2 : h_3 = 1 : 3 : 5 .
  3. Formulate Relation: From the ratio, we can express h1h_1 in terms of others: h1=h23h_1 = \frac{h_2}{3} h1=h35h_1 = \frac{h_3}{5} Combining these gives: h1=h23=h35h_1 = \frac{h_2}{3} = \frac{h_3}{5}
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