Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

A uniform conducting wire of length $12a$ and resistance ' $R$ ' is wound up as a current carrying coil in the shape of, (i) an equilateral triangle of side ' $a$ '. (ii) a square of side ' $a$ '. The magnetic dipole moments of the coil in each case respectively are

$\sqrt{3} \, Ia^2$ and $3 \, Ia^2$

$3 \, Ia^2$ and $Ia^2$

$3 \, Ia^2$ and $4 \, Ia^2$

$4 \, Ia^2$ and $3 \, Ia^2$

Step-by-Step Solution

Current in the loop will be $I = V/R$ which is same for both loops. Magnetic moment of Triangle loop = $NIA$ . $M_1 = (\frac{12a}{3a}) \cdot I \cdot \frac{\sqrt{3}}{4} a^2 = \sqrt{3}Ia^2$ . Magnetic moment of square loop = $N'IA' = (\frac{12a}{4a}) \cdot I \cdot a^2 = 3Ia^2$ .

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