Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

A person sitting on the ground floor of a building notices through the window, of height $1.5 \text{ m}$ , a ball dropped from the roof of the building crosses the window in $0.1 \text{ s}$ . What is the velocity of the ball when it is at the topmost point of the window? ( $g=10 \text{ m/s}^2$ )

15.5 m/s

14.5 m/s

4.5 m/s

20 m/s

Step-by-Step Solution

Identify the Given Variables: Displacement (height of the window), $s = 1.5 \text{ m}$ Time taken to cross the window, $t = 0.1 \text{ s}$ Acceleration due to gravity, $a = g = 10 \text{ m/s}^2$ Initial velocity at the top of the window, $u = ?$
Select the Kinematic Equation: Use the second equation of motion which relates displacement, initial velocity, time, and acceleration . $s = ut + \frac{1}{2}at^2$
Substitute and Solve: $1.5 = u(0.1) + \frac{1}{2}(10)(0.1)^2$ $1.5 = 0.1u + 5(0.01)$ $1.5 = 0.1u + 0.05$ $0.1u = 1.5 - 0.05$ $0.1u = 1.45$ $u = \frac{1.45}{0.1} = 14.5 \text{ m/s}$

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