The self-inductance ($L$) of a coil is defined by the relationship between the total magnetic flux linkage ($N\Phi_B$) and the current ($I$) flowing through it: $N\Phi_B = LI$ .

Given: Number of turns ($N$) = 1000 Current ($I$) = $4 \text{ A}$

• Magnetic flux per turn ($\Phi_B$) = $4 \times 10^{-3} \text{ Wb}$

Calculation:

1. Calculate Total Flux Linkage: $\text{Total Flux} = N \times \Phi_B$ $\text{Total Flux} = 1000 \times (4 \times 10^{-3}) \text{ Wb} = 4 \text{ Wb}$

2. Calculate Self-Inductance ($L$): Using the formula $LI = N\Phi_B$: $L = \frac{N\Phi_B}{I}$ $L = \frac{4 \text{ Wb}}{4 \text{ A}}$ $L = 1 \text{ H}$