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NEET PHYSICSEasy

A nucleus of mass number 189 splits into two nuclei having mass number 125 and 64. The ratio of radius of two daughter nuclei respectively is

A

1 : 1

B

4 : 5

C

5 : 4

D

25 : 16

Step-by-Step Solution

Radius of nuclei with mass number A varies as R=R0A1/3R = R_0 A^{1/3}. Therefore, R1R2=(12564)1/3=54=5:4\frac{R_1}{R_2} = \left(\frac{125}{64}\right)^{1/3} = \frac{5}{4} = 5:4.

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