Method 1: Work-Energy Theorem The work done by the resistive force ($F$) equals the change in kinetic energy [Source 93, 95]. $W = \Delta K = K_f - K_i$ $-F \cdot s = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$ $F \cdot s = \frac{1}{2}mu^2$ $F = \frac{mu^2}{2s}$

Calculation: $F = \frac{0.02 \times (250)^2}{2 \times 0.12}$ $F = \frac{0.02 \times 62500}{0.24}$ $F = \frac{1250}{0.24} \approx 5208.33 \text{ N}$

Scientific Notation: $F \approx 5.2 \times 10^3 \text{ N}$ (This approach aligns with Example 4.2 in Source 79, which uses kinematic equations and Newton's second law to solve a similar bullet-block problem).