A thermodynamic system undergoes a cyclic process as shown in Fig. The work done by the system in the cycle is:
zero
The work done by a thermodynamic system during a cyclic process is equal to the net area enclosed by the cycle on a P-V diagram.
In this specific problem (referencing a standard AIPMT 2014 figure implied by the answer), the cycle typically involves two loops of equal area: one traced clockwise (positive work) and the other counter-clockwise (negative work). If the areas are equal, the positive and negative work cancel each other out, resulting in zero net work done by the system.
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