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A charged particle having drift velocity of 7.5×10−4 m s−17.5 \times 10^{-4} \text{ m s}^{-1} in an electric field of 3×10−10 Vm−13 \times 10^{-10} \text{ Vm}^{-1}, has a mobility in m2 V−1 s−1\text{m}^2 \text{ V}^{-1} \text{ s}^{-1} of :

1

2.25 \times 10^{15}

2

2.5 \times 10^{6}

3

2.5 \times 10^{-6}

4

2.25 \times 10^{-15}

Step-by-Step Solution

Mobility, μ=vdE=7.5×10−43×10−10=2.5×106 m2V−1s−1\mu = \frac{v_d}{E} = \frac{7.5 \times 10^{-4}}{3 \times 10^{-10}} = 2.5 \times 10^6 \text{ m}^2 \text{V}^{-1} \text{s}^{-1}.

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