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NEET PHYSICSEasy

An object is moving with a uniform acceleration which is parallel to its instantaneous direction of motion. The displacement (s) – velocity (v) graph of this object is

A

[Image/Empty]

B

[Image/Empty]

C

4

D

[Image/Empty]

Step-by-Step Solution

  1. Kinematic Equation: For an object moving with uniform (constant) acceleration aa along a straight line, the relationship between displacement ss, final velocity vv, and initial velocity uu is given by the third equation of motion: v2=u2+2asv^2 = u^2 + 2as .
  2. Mathematical Relationship: Rearranging the equation to solve for displacement ss, we get s=v2u22as = \frac{v^2 - u^2}{2a}. This equation indicates that displacement ss is proportional to the square of the velocity (sv2s \propto v^2).
  3. Graphical Shape: A relationship where one variable is proportional to the square of the other (yx2y \propto x^2) represents a parabola. Therefore, the graph plotting displacement (ss) against velocity (vv) will be a parabolic curve.
  4. Conclusion: The correct graph corresponding to this motion is a parabola. Assuming the option labeled '4.' depicts a parabola (as per standard solutions for this AIIMS PYQ), it is the correct representation.
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