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NEET PHYSICSEasy

A lift of mass 1000 kg1000 \text{ kg} is moving with an acceleration of 1 m/s21 \text{ m/s}^2 in the upward direction. Tension developed in the string, which is connected to the lift, is:

A

9,800 N

B

10,000 N

C

10,800 N

D

11,000 N

Step-by-Step Solution

According to Newton's second law of motion, the net force on an object moving upward with acceleration aa is the result of the upward tension (TT) overcoming the downward weight (mgmg).

The equation of motion is: Tmg=maT - mg = ma T=m(g+a)T = m(g + a)

Given: Mass, m=1000 kgm = 1000 \text{ kg} Acceleration, a=1 m/s2a = 1 \text{ m/s}^2

  • Acceleration due to gravity, g=9.8 m/s2g = 9.8 \text{ m/s}^2 (standard value)

Substituting the values: T=1000 kg×(9.8 m/s2+1 m/s2)T = 1000 \text{ kg} \times (9.8 \text{ m/s}^2 + 1 \text{ m/s}^2) T=1000×10.8 NT = 1000 \times 10.8 \text{ N} T=10,800 NT = 10,800 \text{ N}

(Note: This concept relates to apparent weight in a lift and effective gravity as seen in Source 73 and 126).

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